Question on: WAEC Mathematics - 2006
(\begin{array}{c|c} x & 1 & 4 & p \ \hline y & 0.5 & 1 & 2.5\end{array}). The table above satisfies the relation y = k(\sqrt{x}), where k is a positive constant. Find the value of K.
A
0.5
B
1
C
1.5
D
2
Ask EduPadi AI for a detailed answer
Correct Option: A
y = k(\sqrt{x}) when y = 1, x = 4
k = (\frac{y}{\sqrt{x}})
= (\frac{1}{\sqrt{4}})
= (\frac{1}{2})
= 0.5
Add your answer
Please share this, thanks!
No responses